Subject: Re: [xsl] generating xml header info from xsl From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Tue, 20 Aug 2002 09:58:51 +0100 |
Hi Bruce, > Is there a way to generate xmlinfo like the following from xsl? > : > <?xml version="1.0"?> > <wizPgDfn xmlns:xsi="http://www.w3.ofr/2001/XMLSchema-instance" > xsi:noNamespaceSchemaLocation="v":\webcit\scemas\wizDfn.xsd"> Assuming that the " here .........^ is an error, then yes. Try the following stylesheet: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <xsl:template match="/"> <wizPgDfn xsi:noNamespaceSchemaLocation="v:\webcit\scemas\wizDfn.xsd" /> </xsl:template> </xsl:stylesheet> (I also changed the URL that you were using for the XML Schema instance namespace so that it was www.w3.org rather than www.w3.ofr but just change it back if you wanted the one you had for some reason.) The XML Schema attributes are treated just the same as any other attributes in XSLT 1.0. Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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