Subject: Re: [xsl] document() function From: "J.Pietschmann" <j3322ptm@xxxxxxxx> Date: Tue, 20 Aug 2002 22:44:32 +0200 |
I am trying to do the following: document('file:///c:/servers/mserver/ojamc2vpt1_part.xsd') to open a document not in the same directory as my stylesheet. It does not work.
What actually is "not work"? Do you get an error, or does the style sheet produce an unexpected (probably empty) result?
For a starter, use a good command line processor like Saxon to check. It will give you a proper error message if the file couldn't be accessed or contains syntax errors or a DTD which could not be accessed. If there is no problem with access, make a simple file containing <xsl:value-of select="name(document('...')/*)"/> This should result in the name of the document element of the file put in the output, otherwise something fishy is going on or you missed an error message. After you've verified the file is properly read, check what you do with the result of the document() call, for example you might have misspelled the match in the template designed to match the document element.
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Newsgroup?, Mulberry Technologie | Thread | [xsl] how to get the next node afte, Ming Yu |
Re: [xsl] document() function, J.Pietschmann | Date | Re: [xsl] document() function, Thomas B. Passin |
Month |