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RE: [xsl] Returning the file name of the input file

Subject: RE: [xsl] Returning the file name of the input file
From: Jarno.Elovirta@xxxxxxxxx
Date: Wed, 28 Aug 2002 10:57:04 +0300
Hi,

> Subject: [xsl] Returning the file name of the input file
> 
> 
> Hello,
> 
> does anybody if the following is possible:
> 
> I want to use the name of the inputfile in the outputfile. So 
> if I want to
> transform the file c:\temp\test.xml, I want to get in my output
> c:\temp\test.xml.

Pass the input filename as a parameter.

Jarno

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