Subject: [xsl] preceding-sibling reversed ? From: "Bjorn Boxstart" <boxstart@xxxxxxxx> Date: Thu, 29 Aug 2002 12:13:22 +0200 |
Hello, I created in an XSL-T stylesheet a variable that contains presentation slides. Each of the slides is a '<div>' element with a 'class' attribute with the value 'slide' and all these elements have and 'id' attribute with a unique value. All slides exist in the same level in the hierarchy of the document. I wanted to add a 'previous' and 'next' button to each slide that (off course) links to the previous and next slide in the presentation. to be able to create the link to the next slide, I used the following lines: <a> <xsl:attribute name="href"> #<xsl:value-of select="following-sibling::div[@class = 'slide']/@id"/> </xsl:attribute> <img src="images/icons/next.gif" border="0"/> </a> This works perfect, however for the previous slide I wanted to use: <a> <xsl:attribute name="href"> #<xsl:value-of select="preceding-sibling::div[@class = 'slide']/@id"/> </xsl:attribute> <img src="images/icons/back.gif" border="0"/> </a> This always results in a link to the first slide (msxml). A bell started to ring and I thought that the listing of the elements probabley would be reversed, so I tried the following: <a> <xsl:variable name="pos" select="position()" /> <xsl:attribute name="href"> #<xsl:value-of select="preceding-sibling::div[@class = 'slide' and position() = $pos -1]/@id"/> </xsl:attribute> <img src="images/icons/back.gif" border="0"/> </a> This also results in a link to the first slide. Now I have the following that works fine, but I don't really understand why! Can anybody please explain me this? <a> <xsl:attribute name="href"> #<xsl:value-of select="preceding-sibling::div[@class = 'slide' and position() = 1]/@id"/> </xsl:attribute> <img src="images/icons/back.gif" border="0"/> </a> thanks in advance! Bjorn Boxstart XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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