Subject: Re: [xsl] Node selection based on parent attribute From: "katharine wykes" <katharinewykes@xxxxxxxxxxx> Date: Fri, 30 Aug 2002 13:59:29 +0000 |
If I use: <xsl:template match="tree"> <xsl:apply-templates select="menu"/> </xsl:template>
<xsl:template match="menu"> <xsl:for-each select="menu[@id=$id]/menu"> <xsl:value-of select="@id"/> </xsl:for-each> </xsl:template>
passing through a parameter of 1 using: <xsl:param name="id" select="menu"/>
From: ronald heller <ronald@xxxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Node selection based on parent attribute Date: Fri, 30 Aug 2002 14:45:37 +0200
<menu id=6> <menu id=7/> <menu id=8/> </menu>
<xsl:for-each "menu[@id=$id]/menu"> <xsl:value-of select="@id"/> </xsl:for-each>
this would get you 7 & 8 as a result if $if would be 6.
cheers RH At 12:32 PM 30-08-02 +0000, you wrote:
Hi,
I would like to produce a list of child nodes from a parent that has a specific attribute value, ie with the following xml structure I want to just retrive the children of the menu node with an id of 6.
<menu id=6>
<menu id=7/>
<menu id=8/>
</menu>
<menu id=9>
<menu id=10/>
<menu id=11/>
</menu>
I have tried
<xsl:for-each "../@id=$id">
<xsl:value-of select="@id"/>
</xsl:for-each>
Using a param passed in from asp.
Am I on the right track, and would the above method be the best to retrieve a certain section of a heirachacal xml structure based on a parent attribute.
I am using asp with the msxml parser.
Thanks in advance.
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