Subject: Re: [xsl] Node selection based on parent attribute From: "katharine wykes" <katharinewykes@xxxxxxxxxxx> Date: Fri, 30 Aug 2002 17:18:40 +0000 |
Any clues as to the cause of this? Cheers,
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] Node selection based on parent attribute Date: Fri, 30 Aug 2002 12:24:31 -0400
Katharine,
Another approach (besides the ones using for-each) is just to use the built-in descent of the tree, as in something like:
<xsl:template match="menu"> <xsl:if select="ancestor::menu[@id=$id']"> <xsl:value-of select="@id"/> <!-- copies out this menu's @id if it has an ancestor menu with @id = $id --> </xsl:if> <xsl:apply-templates/> <!-- continues the tree traversal in case there are any below --> </xsl:template>
Make sure the parameter is set to the *value* of the id ('1', '6', whatever) whose descendants you want.
Cheers, Wendell
At 10:51 AM 8/30/2002, you wrote:Thanks for that.
Would there be an easy way of making that recursive. So if there were sub/sub nodes under <menu id=6>, ie
<menu id=6>
<menu id=8>
<menu id=9/>
<menu id=10/>... and so on
</menu>
</menu>
====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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