Subject: Re: [xsl] Getting the XPath of a node From: Peter Davis <pdavis152@xxxxxxxxx> (by way of Peter Davis <pdavis152@xxxxxxxxx>) Date: Wed, 4 Sep 2002 02:46:23 -0700 |
On Wednesday 04 September 2002 02:44, you wrote: > reverse document order I'm an idiot, please ignore that. You can use <xsl:for-each select="ancestor-or-self::*>, as Mike Brown said, instead of my stupid recursive template. -- Peter Davis XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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