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Subject: [xsl] What is the probelem with this standard code???????????? From: "Sachidanandam E K" <sachidanandam.kumaraswamy@xxxxxxxxxxxxxx> Date: Wed, 11 Sep 2002 23:45:01 +0530 |
Below code is really not working.Though it is a basic code.And I amdam sure
I am doing this every day in various applications.But suddenly this pieace
of code is not working.But no error is returned.
When I used Xselerator and transfom i am geting the result clearly.
No hints yet.Any clues!!?
try
{
var oXmlStylesheet1 = new
ActiveXObject("MSXML2.FreeThreadedDOMDocument");
var oXmlSource1 = new
ActiveXObject("MSXML2.FreeThreadedDOMDocument");
var oXmlOutput1 = new
ActiveXObject("MSXML2.FreeThreadedDOMDocument");
var oXslTemplate1 = new ActiveXObject("MSXML2.XSLTemplate");
oXmlStylesheet1.async = false;
oXmlOutput1.async = false;
oXmlSource1.async = false;
//alert(strHierarchyXML);
if (! oXmlSource1.loadXML(strHierarchyXML))
if (! oXmlStylesheet1.load("templates/ToolagentTree.xsl"))
alert("RMSTreeControlError: Error occured accessing URL:
templates\\ToolagentTree.xsl, Description:" + oXmlSource.parseError);
//alert(oXmlSource1.xml);
//alert(oXmlStylesheet1.load("templates/ToolagentTree.xsl"));
//alert(oXmlStylesheet1.xml);
//alert(oXmlStylesheet1.url);
oXslTemplate1.stylesheet = oXmlStylesheet1;
var oXslProcessor1 = oXslTemplate1.createProcessor();
oXslProcessor1.input = oXmlSource1;
oXslProcessor1.output = oXmlOutput1;
oXslProcessor1.addParameter("InstrumentType", "ES20>/Stepper02/")
oXslProcessor1.transform()
alert(oXmlOutput1.xml);
}
catch(e)
{
alert(e.description);
}
Sachidanandam.E.K
Member Techinical Staff
HCLT KT-ODC
sachidanandam.kumaraswamy@xxxxxxxxxxxxxx
<mailto:sachidanandam.kumaraswamy@xxxxxxxxxxxxxx>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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