Re: [xsl] document() loops

Subject: Re: [xsl] document() loops
From: "Laura Jenkins" <xsl_list@xxxxxxxxxxx>
Date: Fri, 13 Sep 2002 11:21:43 +0000
oh ic what u mean.. then in such a case , how do we run a for loop for an imported xml file???
for.example
if i get the locations from running a for-each to mainxml.xml
and get hold of the first univ-xml's name..
<xsl:for-each select="document(/univ-xml-list/univ-xml)">
<xsl:variable name = "external-xml" select ="document(.)"/>
</xsl:for-each>


Now is there a way to run a for-each for this external xml file??
so that i get hold of EACH ELEMENT in the External XML?? and get hold of their properties like name() position() etc??



From: David Carlisle <davidc@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
CC: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] document() loops
Date: Fri, 13 Sep 2002 10:19:21 +0100

  <xsl:for-each select="document(/univ-xml-list/univ-xml[1])">
  <xsl:variable name = "element-name" select="name(.)"/>
  <xsl:element name="$element-name">


</xsl:element> </xsl:for-each> this will create all the elements that are in the first elements..

No it won't as I said before that for-each is iterating over a single node
so it will only create one element, with name equal to teh name of teh
node selected in the xsl:for-each select=" however that node is a
document node, so has name "" so the xsl:eleemnt should generate an
error thatyou are trying to generate an element with an invalid name,
"".


David


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