Subject: Re: [xsl] document() loops From: "Laura Jenkins" <xsl_list@xxxxxxxxxxx> Date: Fri, 13 Sep 2002 11:21:43 +0000 |
From: David Carlisle <davidc@xxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx CC: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] document() loops Date: Fri, 13 Sep 2002 10:19:21 +0100
<xsl:for-each select="document(/univ-xml-list/univ-xml[1])"> <xsl:variable name = "element-name" select="name(.)"/> <xsl:element name="$element-name">
</xsl:element> </xsl:for-each> this will create all the elements that are in the first elements..
No it won't as I said before that for-each is iterating over a single node so it will only create one element, with name equal to teh name of teh node selected in the xsl:for-each select=" however that node is a document node, so has name "" so the xsl:eleemnt should generate an error thatyou are trying to generate an element with an invalid name, "".
David
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