Subject: Re: [xsl] grouping probs From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Mon, 16 Sep 2002 10:40:46 +0100 |
Hi Laura, > Essentially it should eleminate the duplicates out of "any" element > it comes across.i cant give conditions based on a fixed element. so > if the xsl comes across elements with same "id" and "text()".. then > it should eleminate the duplicating element "where ever found in the > document" Set up a key that matches all elements that doesn't hold any child elements and assigns them a value based on their id (presumably an id attribute? Or did you mean the name of the element?) and string value: <xsl:key name="duplicates" match="*[not(*)]" use="concat(@id, '+', string())" /> Use an identity template to do a recursive copy of the whole document: <xsl:template match="node() | @*"> <xsl:copy> <xsl:apply-templates select="@* | node()" /> </xsl:copy> </xsl:template> and override this template for elements that don't have element children: <xsl:template match="*[not(*)]"> ... </xsl:template> You only want to copy these elements if they are the first element in the document with that id and value. Use the classic Muenchian test to see whether they're the first element in the document with that id and string value: <xsl:template match="*[not(*)]"> <xsl:if test="generate-id() = generate-id(key('duplicates', concat(@id, '+', string()))[1])"> <xsl:copy> <xsl:apply-templates select="@* | node()" /> </xsl:copy> </xsl:if> </xsl:template> And there you go. Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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