[xsl] Is it possible to group by name() ?

["Casadome, Francisco" <Francisco.Casadome@xxxxxxxxxxxxxx>]

Hi all,

I would appreciate some help on this. I have an XML that looks like this:

<n0>
	<n1>
		<a>text</a>
		<b>text</b>
		<c>text</c>
	</n1>
	<n1>
		<a>text</a>
		<c>text</c>
	</n1>
	<n1>
		<a>text</a>
		<b>text</b>
		<d>text</d>
	</n1>
</n0>

And what I would like to have is a list of the different nodes inside n1
nodes.
In the example above, the result should be: a,b,c,d.

Is it possible to do something like this ?
<xsl:key name="groupbyname" match="/n0/n1/*" use="name()"/>

And then use the muenchian method ? But how ?

Thanks a lot,
Frank
	

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