Re: [xsl] testing element's contents

[Joerg Heinicke <joerg.heinicke@xxxxxx>]

Hi Nathan,

it should work in your example too, because there is a text node as 
child of the <Link>, so the test is passed.

Only one comment:

<p>
    <Link>

    </Link>
</p>

The above passes the test because of spaces and line breaks between <p> 
and <Link> or between <Link> and </Link>. To avoid this you can test on 
nodes, which don't consist of only whitespaces characters. Use 
normalize-space() for this 
(http://www.w3.org/TR/xpath#function-normalize-space):

<xsl:when test="descendant::node()[normalize-space()][not(self::Link or 
self::Media)]">
    <p><xsl:apply-templates/></p>
</xsl:when>

=> If a descendant node exists, that consists not only of whitespace 
characters, that is not <Link> or <Media>, wrap it in <p>.

Regards,

Joerg

Nathan Shaw wrote:
> Excellent Joerg! The only place this would not work is
> if I have a paragraph element with only a Link element
> in it, such as:
>
> <p><Link href="blah.html">This is a link</Link></p>
>
> I need those to pass through the test and be wrapped
> in a p tag. Otherwise, it catches everything else I
> need!
>
> Thank you! That gives me great direction...
>
> --nate
>
>
> --- Joerg Heinicke <joerg.heinicke@xxxxxx> wrote:
>
> > <xsl:when test="descendant::node()[not(self::Link or
> > self::Media)]">
> >   <p><xsl:apply-templates/></p>
> > </xsl:when>
> >
> > If there is any descendant node (including elements,
> > comments, PIs, 
> > text), which is not element Link or element Media,
> > create <p> in output 
> > tree.
> >
> > Regards,
> >
> > Joerg
> >
> > Nathan Shaw wrote:
> >
> > > hi all,
> > >
> > > Thanks to everyone who gave me advice on my
> >
> > previous
> >
> > > post about images and captions. Now, I have
> >
> > another
> >
> > > tricky lil' xslt problem. If a paragraph element
> > > contains ONLY a media element OR a media element
> > > surrounded by a link element and nothing more
> >
> > (read,
> >
> > > no other nodes, be they text or not), such as:
> > >
> > > <p><img
> > > src="http://www.mylocal.gov/images/nasausa.gif";
> > > height="255" width="432"/></p>
> > >
> > > I need to strip the p tags out of resulting
> >
> > output.
> >
> > > However, if it does contain other nodes, such as:
> > >
> > > <p><img
> > > src="http://www.mylocal.gov/images/nasausa.gif";
> > > height="255" width="432"/>This is my news release.
> >
> > The
> >
> > > authors will be typing the news release content in
> > > here! I am not sure what this news release is even
> > > about, but lets see how it comes out in XML, shall
> >
> > we?
> >
> > > As I see it coming out as:</p>
> > >
> > > I need to leave it alone.
> > >
> > > Here is what I have so far. It only looks to see
> >
> > if a
> >
> > > media element or a media element wrapped by a link
> > > element exists, but does not consider if there is
> >
> > a
> >
> > > text node after a media or link element.
> > >
> > > <xsl:template match="p">
> > > <xsl:choose>
> > > 	<xsl:when test="((descendant::*[1])[self::Link]
> >
> > and
> >
> > > (descendant::*[2])[self::Media]) or
> (descendant::*[1])[self::Media]"><xsl:apply-templates
>
> > > /></xsl:when>
> > > 	<xsl:otherwise><p><xsl:apply-templates
> > > /></p></xsl:otherwise>
> > > </xsl:choose>
> > > </xsl:template>
> > >
> > > Thoughts? Ideas? Criticisms?
> > >
> > > --nate


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