Re: [xsl] Select a node by name

Subject: Re: [xsl] Select a node by name
From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx>
Date: Fri, 04 Oct 2002 19:35:55 +0300
Andreas Schlegel wrote:

 <person name="Bill" job="Developer"/>
 <person name="Steve" job="Admin"/>
 <person name="Betty" job="CEO"/>

A statement like <xsl:value-of select="person"/> won't help because I have a lot of nodes of the type PERSON.

If I have a node already selected I may use <xsl:value-of select="@name"/>

It's no problem to do it by for each ( <xsl:for-each select="person"> ). But I look for a way to pick a person out of the list, i.e. "Betty".

That's xpath basics, what you need is just person[@name='Betty'], what means in english "Select all person elements children of the current node, which have attribute name with string value 'Betty'".
For more info see xpath recommendation at

Oleg Tkachenko
eXperanto team
Multiconn International, Israel

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