Re: [xsl] Select a node by name

[Oleg Tkachenko <olegt@xxxxxxxxxxxxx>]

Andreas Schlegel wrote:

> <persons>
>  <person name="Bill" job="Developer"/>
>  <person name="Steve" job="Admin"/>
>  <person name="Betty" job="CEO"/>
> </persons>
>
> A statement like <xsl:value-of select="person"/> won't help because I 
> have a lot of nodes of the type PERSON.
>
> If I have a node already selected I may use <xsl:value-of select="@name"/>
>
> It's no problem to do it by for each ( <xsl:for-each select="person"> ). 
> But I look for a way to pick a person out of the list, i.e. "Betty".

That's xpath basics, what you need is just person[@name='Betty'], what 
means in english "Select all person elements children of the current 
node, which have attribute name with string value 'Betty'".
For more info see xpath recommendation at http://www.w3.org/TR/xpath.

--
Oleg Tkachenko
eXperanto team
Multiconn International, Israel


XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list