[xsl] How can I get the XPATH of the current node ?

Subject: [xsl] How can I get the XPATH of the current node ?
From: "Louis Meigret" <meigret@xxxxxxxxxxxxxxxx>
Date: Thu, 10 Oct 2002 13:59:57 -0500
First of all, thanks a lot to J?g for pointing me to the Muenchian method.Relentlessly learning.

I have another question : I would like to get the Xpath value of the current node. I am done some homework and tried this method suggested by Jeni Tennison : 

?To get an XPath that's guaranteed to be unique, you need to use the index of the element within its parent rather than its attributevalues. An easy way is to use recursion with the ancestor-or-self axis:

  <xsl:for-each select="ancestor-or-self::*">
    <xsl:text />/<xsl:value-of select="name()" />
    <xsl:text />[<xsl:number />]<xsl:text />


Jeni ?
Unfortunately, this does not print any number between the square brackets (with Xalan). I thought of adding value="position()", but this would be the position within this context (the for-each), not very useful.

Any suggestion to solve what would be useful debugging information (in my case) ?



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