Subject: [xsl] [xsl-fo] generating the correct number of columns for a table from html to xsl-fo From: Jaish_Kumar@xxxxxxxxxxxxx Date: Tue, 15 Oct 2002 09:24:07 +0530 |
Jaish Kumar Apex,Ph. no. 5351194,5351027 extn 141 " Pessimist always looks for difficulty in opportunity and Optimist always looks for opportunity in difficulty " ----- Forwarded by Jaish Kumar/Product/Apex on 14/06/2002 09:19 AM ----- "El Hage Camille" <CAMILLE.ELHAGE@xxxxxxxxxxx To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> l.com> cc: Sent by: Subject: [xsl] [xsl-fo] generating the correct owner-xsl-list@xxxxxxxxxxxx number of columns for a table from html to xsl-fo rytech.com 14/10/2002 10:20 PM Please respond to xsl-list Hi all, I need to generate a table in xsl-fo from an html table. My problem is that in FO, you need to declare the number of columns before starting the body. On the FAQ, I only found the (enlightening) discussion on how to get the maximum number of child nodes ( http://www.biglist.com/lists/xsl-list/archives/200101/msg00177.html), but the resulting code gives a number and I don't know how to use that. My question is: if I have a number (say "8"), how do I loop through to generate 8 times the line : <fo:table-column column-width="2cm"/> ? thanks for any help. Camille XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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