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Subject: [xsl] [xsl-fo] generating the correct number of columns for a table from html to xsl-fo From: Jaish_Kumar@xxxxxxxxxxxxx Date: Tue, 15 Oct 2002 09:24:07 +0530 |
Jaish Kumar
Apex,Ph. no. 5351194,5351027 extn 141
" Pessimist always looks for difficulty in opportunity and Optimist always
looks for opportunity in difficulty "
----- Forwarded by Jaish Kumar/Product/Apex on 14/06/2002 09:19 AM -----
"El Hage Camille"
<CAMILLE.ELHAGE@xxxxxxxxxxx To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
l.com> cc:
Sent by: Subject: [xsl] [xsl-fo] generating the correct
owner-xsl-list@xxxxxxxxxxxx number of columns for a table from html to xsl-fo
rytech.com
14/10/2002 10:20 PM
Please respond to xsl-list
Hi all,
I need to generate a table in xsl-fo from an html table. My problem is that
in FO, you need to declare the number of columns before starting the body.
On the FAQ, I only found the (enlightening) discussion on how to get the
maximum number of child nodes (
http://www.biglist.com/lists/xsl-list/archives/200101/msg00177.html), but
the resulting code gives a number and I don't know how to use that.
My question is: if I have a number (say "8"), how do I loop through to
generate 8 times the line : <fo:table-column column-width="2cm"/> ?
thanks for any help.
Camille
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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