Subject: RE: [xsl] Fwd: Built-in *@ vs. node() From: Jarno.Elovirta@xxxxxxxxx Date: Wed, 16 Oct 2002 18:20:25 +0300 |
Hi, > <?xml version="1.0" encoding="iso-8859-1"?> > <xsl:stylesheet > version="1.0"xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output method="xml" encoding="iso-8859-1" indent="yes"/> > > <xsl:template match="node()"> > <xsl:copy> > <xsl:apply-templates select="@*"/> > <xsl:apply-templates/> > </xsl:copy> > </xsl:template> > > </xsl:stylesheet> > > It doesnt copy attribute nodes and i dont know why it doesnt. It > matches the default attribute template which i thought would be > overriden by <xsl:template match="node()"> Nope, because "node()" pattern uses the child axis, and while attributes are nodes, they are accessible only using the "attribute" axis or abbreviation "@" . Thus use <xsl:template match="@*|node()"> ... Cheers, Jarno XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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