RE: [xsl] Re: Is it possible to know position of ancestor?

["Dion Houston" <dionh@xxxxxxxxxxxxxxxxxxxxx>]

Here's another way to do it, and this works regardless of the namespace:

         <xsl:for-each select="..">
            <xsl:number/>
         </xsl:for-each>

Here's how it works:

<xsl:for-each> iterates through each of the nodes in the selected
nodeset.  In this case, that nodeset contains only one node, the parent.
<xsl:number> by default returns the sequence number of the current node
within the context of like named nodes at the same level.  

HTH!

Dion
-----Original Message-----
From: James Carlyle [mailto:james.carlyle@xxxxxxxxxxxx] 
Sent: Thursday, October 17, 2002 1:28 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] Re: Is it possible to know position of ancestor?

If you are not using namespaces, this will work

count(parent::*/preceding-sibling::*[name() =
name(current()/parent::*)]) +
1

Kind regards,

James Carlyle


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of
> evgeniy.strokin@xxxxxxxxxxxxxxxx
> Sent: 17 October 2002 21:02
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Re: Is it possible to know position of ancestor?
>
>
> But if you don't know name of element "line"? It should be the same
name
> only this you know.
>
> Thanks,
> Jenya
>
> James Carlyle writes:
>
> > Try
> >
> > select="count(../preceding-sibing::line + 1)"
> >
> > Kind regards,
> >
> > James Carlyle
> >
> >> -----Original Message-----
> >> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> >> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of
> >> evgeniy.strokin@xxxxxxxxxxxxxxxx
> >> Sent: 17 October 2002 20:11
> >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> >> Subject: [xsl] Re: Is it possible to know position of ancestor?
> >>
> >>
> >> Yes, you are so right (how do you know what I meant if I didn't
> >> know!?!? :)
> >> But here is also the problem:
> >> Let say we have another XML:
> >> <root>
> >>  <some_tag/>
> >>  <line>
> >>    <a/>
> >>    <b/>
> >>  </line>
> >>  <line>
> >>    <a/>
> >>    <b/> - we are here
> >>  </line>
> >> <root>
> >>
> >> In your example select="count(../preceding-sibing::* + 1)" we get
> >> 3 because
> >> it will count "some_tag" too. But we need to count only "line"
> elements.
> >> How we can solve this problem?
> >>
> >> Jenya
> >>
> >>
> >> David Carlisle writes:
> >>
> >> >
> >> >> We are in tag "b",
> >> > note that xslt works on elements (element nodes) not tags,
> and importat
> >> > distinction.
> >> >
> >> >>  We want to find out what is position of our ancestor
> >> >> in their ancestor.
> >> >
> >> > I think you mean parent rather than ancestor:
> >> >
> >> >  select="count(../preceding-sibing::* + 1)"
> >> >
> >> >
> >> > David
> >>
> >>
> >>  XSL-List info and archive:
http://www.mulberrytech.com/xsl/xsl-list
> >>
> >
> >  XSL-List info and archive:
http://www.mulberrytech.com/xsl/xsl-list
> >
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list