Re: [xsl] Top n values

["Vasu Chakkera" <vasucv@xxxxxxxxxxx>]

..continued from previous mail..
you can also do without node-set()..
<xsl:for-each select="/root/item">
<xsl:sort select="." order="descending" data-type="number"/>
<xsl:if test="position()&lt;=3">
<xsl:value-of select="."/><br/>
</xsl:if>
</xsl:for-each>


> From: Dan Diebolt <dandiebolt@xxxxxxxxx>
> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Top n values
> Date: Thu, 17 Oct 2002 12:30:04 -0700 (PDT)
>
> I need to process the top n values in a list where n
> is dynamic. So if n=3 and I had the following XML:
>
> <root>
>  <item>1</item>
>  <item>5</item>
>  <item>3</item>
>  <item>2</item>
>  <item>6</item>
>  <item>4</item>
> </root>
>
> I need to process <item>'s with values 6,5,4. If I had
> captured n in a variable/parameter, what is the most
> efficient way to do this? What I want to avoid is walking
> the <item> nodset multiple times as there are a lot of
> <item>s (thousands). Thanks.
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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