Re: [xsl] what could select="self:node()[false()] be for?

Subject: Re: [xsl] what could select="self:node()[false()] be for?
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Fri, 18 Oct 2002 15:42:35 +0200
It returns a empty nodeset by default.

self::node() means the current node. false() evaluates to false of course, so the current node is filtered out.

Regards,

Joerg

Tom Amiro wrote:
XSLTC compiles the following template but at runtime throws an error. Does anyone have a clue what the line

<xsl:param name="data" select="self::node()[false()]"/>

could be doing; is supposed to do; does it make any sense?

<xsl:template name="POP_UP">
<xsl:param name="id"/>
<xsl:param name="data" select="self::node()[false()]"/>
</xsl:template>

Tom Amiro

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