Re: [xsl] XPath expr on generated nodeset

[David Carlisle <davidc@xxxxxxxxx>]

   <xsl:variable name="aFrag">
      <xsl:element name="aaa">
        <xsl:element name="bbb">Stuff</xsl:element>
      </xsl:element>
    </xsl:variable> 


that is just a long way of writing

   <xsl:variable name="aFrag">
      <aaa>
        <bbb>Stuff</bbb>
      </aaa>
    </xsl:variable>

in particular it generates nodes in the default namepsace which in your
case is
 xmlns="automationgroups.com/docdebug"

however Xpath "$aNd//bbb looks for bbb in no namespace, you want
"$aNd//x:bbb
and  xmlns:x="automationgroups.com/docdebug" somewhere above so the x:
prefix is in scope.

David

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