Re: [xsl] changing node names in XML

Subject: Re: [xsl] changing node names in XML
From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx>
Date: Sat, 26 Oct 2002 12:08:05 +0100
> <xsl:template match="employee[count(child::*)&gt;0]">
> <xsl:template match="employee[count(child::*)=0]">
> I'm sure there are better ways ...

The following could have been better..
 <xsl:template match="employee[node()]">
 <xsl:template match="employee[not(node())]">
 <xsl:template match="employee[*]">
 <xsl:template match="employee[not(*)]">

We had a discussion some time back regarding which is the best way to check
if there are any child elements..
counting the number of child nodes is not the best way of checking it.


>if you go
> test="count(*)=0">
>then the semantics of count(*) would seem to imply that the system need
>check exactly how many there are (which may take longer of there are
>1000000001 of them. On the other hand the chances are that your system
>will optimise both of these expressions to some internal system-specific
>test-if-empty function and so it probably doesn't make any difference
>what you do.



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