RE: [xsl] Sorting on a transformed string?

["Michael Kay" <michael.h.kay@xxxxxxxxxxxx>]

The simplest way of doing this in XSLT 1.0 is probably to use a
multi-pass transformation. In the first pass, build a temporary tree
containing the computed sort keys. In the second pass (done using
xx:node-set()), do the sort.

In XSLT 2.0 you can compute the sort key using an xsl:function.

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Scott Bronson
> Sent: 26 October 2002 17:58
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Sorting on a transformed string?
> 
> 
> Hello.  A sort problem is stumping me right now.  I've got 
> the following
> nodes:
> 
>     <Member name="CreateInstance">
>     <Member name="System.Caption.Insert">
>     <Member name="System.Collections.ICollection.Count"
> 
> I'd like to sort them by name, without leading namespace:
> 
>     Count, CreateInstance, Insert
> 
> Then I'd like to output them, WITH the namespace:
> 
>     System.Collections.ICollection.Count
>     CreateInstance
>     System.Caption.Insert
> 
> Normally, I use leaf-name (below) to trim the namespace.  
> However, I suspect it's impossible to get sort to use a named 
> template, and I haven't figured out any other way of figuring 
> out the leaf name.
> 
> Is possible to sort on the leaf name?  Is it possible in XML 1.0?  :)
> 
> Thank you!
> 
>     - Scott
> 
> 
> 
> <xsl:template name="leaf-name">
>   <xsl:param name="string"/>
>   <xsl:choose>
>     <xsl:when test="substring-after($string,'.')">
>       <xsl:call-template name="leaf-name">
>         <xsl:with-param name="string" 
> select="substring-after($string,'.')"/>
>       </xsl:call-template>
>     </xsl:when>
>     <xsl:otherwise>
>       <xsl:value-of select="$string"/>
>     </xsl:otherwise>
>   </xsl:choose>
> </xsl:template>
> 
> 
> 
> 
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> 


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