RE: [xsl] Delete XML Node

[Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>]

Deepak,

At 11:29 AM 11/1/2002, I wrote:
> > > Or more simply, if a Y will never have more than one B, you can do
> > >
> > > <xsl:template match="B">
> > >   <B1>
> > >     <xsl:apply-templates/>
> > >   </B1>
> > > </xsl:template>
>
> This allows your rule (finding that you need a Y since you have a B='ABC') 
> to be in one place, which is better; the down side is that if you have 
> input like
>
> <Y>
>   <B>ABC</B>
>   <B>LMN</B>
>   <C>zzz</C>
> <Y>
>
> And your rules are only in the Y template, since "B[.='ABC'] or 
> C[.='XYZ']" is true, all B and C elements will be processed.

Of course the simpler solution to this (doh!) is:

<xsl:template match="Y">
  <xsl:if test="B[.='ABC'] or C[.='XYZ']">
    <Y1>
      <xsl:apply-templates select="B[.='ABC'] | C[.='XYZ']"/>
    </Y1>
  </xsl:if>
</xsl:template>

or the analogous logic. Then you need no logic in the B template.

Incidentally, this can be further compressed (if you like) as:

<xsl:template match="Y[B[.='ABC'] or C[.='XYZ']]">
  <Y1>
    <xsl:apply-templates select="B[.='ABC'] | C[.='XYZ']"/>
  </Y1>
</xsl:template>

<xsl:template match="Y"/> <!-- this suppresses a Y unless it matches the 
other template -->

Cheers,
Wendell


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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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