Re: [xsl] xsl:number useless with xsl:sort?

Subject: Re: [xsl] xsl:number useless with xsl:sort?
From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx>
Date: Mon, 4 Nov 2002 09:50:45 -0000
Hi Jan,

<xsl:number> gives you the position of the element in the source tree, not
in the sorted sequence. What you need to do is a two-phase transformation:
1.create a temporary tree that contains the sorted elements
2.then process this (using xx:node-set()) to add the numbers.
HTH
Vasu
----- Original Message -----
From: "Jan Krattiger" <jan.krattiger@xxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, November 04, 2002 9:08 AM
Subject: [xsl] xsl:number useless with xsl:sort?


> hi folks
>
> i need your help again.
>
> i use xsl:sort to sort the output. now i need something like xsl:number to
> give the elements numbers from 1-n, but i need the sorted one to be
> numbered.
> xsl:number uses the unsorted, "original" xml to number. one possiblity
would
> be sorting the xml before transforming... but that not possible in my
case..
>
> does anyone have a solution?
>
> thanks
>
> Jan
>
> Software Developer
>
> Unit.Net AG
> Thurgauerstrasse 54
> CH - 8050 Zurich
>
> Email:   jan.krattiger@xxxxxxxx
> Web:     http://unit.net
>
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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