Subject: Re: [xsl] xsl:number useless with xsl:sort? From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx> Date: Mon, 4 Nov 2002 09:50:45 -0000 |
Hi Jan, <xsl:number> gives you the position of the element in the source tree, not in the sorted sequence. What you need to do is a two-phase transformation: 1.create a temporary tree that contains the sorted elements 2.then process this (using xx:node-set()) to add the numbers. HTH Vasu ----- Original Message ----- From: "Jan Krattiger" <jan.krattiger@xxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Monday, November 04, 2002 9:08 AM Subject: [xsl] xsl:number useless with xsl:sort? > hi folks > > i need your help again. > > i use xsl:sort to sort the output. now i need something like xsl:number to > give the elements numbers from 1-n, but i need the sorted one to be > numbered. > xsl:number uses the unsorted, "original" xml to number. one possiblity would > be sorting the xml before transforming... but that not possible in my case.. > > does anyone have a solution? > > thanks > > Jan > > Software Developer > > Unit.Net AG > Thurgauerstrasse 54 > CH - 8050 Zurich > > Email: jan.krattiger@xxxxxxxx > Web: http://unit.net > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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