RE: [xsl] looping through Elements stored in a variable..

["Michael Kay" <michael.h.kay@xxxxxxxxxxxx>]

If it were possible to do this in XSLT 1.0 without using the
xx:node-set() extension, then the xx:node-set() extension would not have
been invented. You're out of luck, I'm afraid. Unless of course you use
an XSLT 1.1 or XSLT 2.0 processor.

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 



> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Laura Jenkins
> Sent: 18 November 2002 17:12
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] looping through Elements stored in a variable..
> 
> 
> Hello people,
> i have the following xsl structure
> 
> <?xml version="1.0"?>
> <xsl:stylesheet version="1.0" 
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>  <xsl:template match="/">
>   <xsl:variable name="univ-var">
>    <University-List>
>     <University id = "1"> University1</University>
>     <University id = "2"> University2</University>
>     <University id = "3"> University3</University>
>     <University id = "4"> University4</University>
>    </University-List >
>   </xsl:variable>
> <!-- i want to iterate through this variable without usiing 
> the extension nodeset..-->
> <!-- something along the lines of .. -->
>   <xsl:for-each select="$place-var/placements/placement">
>   <xsl:value-of select="."/>
>   </xsl:for-each>
>  </xsl:template>
> </xsl:stylesheet>
> 
> What i was doing obviousl;y does not work because it needs to 
> be a nodeset. Can any one tell me how to do this without 
> using the extension : nodeset. Its is  MANDATORY that I  DO 
> NOT USE the extension nodeset. Thanks
> 
> 
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> 


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