Re: [xsl] xsl:key on variable containing result of apply-templates

[Grainne Reilly <greilly1@xxxxxxxxx>]

Jorge,
I mistyped your solution when I tried it first - sorry!  After a good 
night's rest I tried it again and it works perfectly!
Thank you, this had been a big help.
Grainne.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:saxon="http://icl.com/saxon";
xmlns:exsl="http://exslt.org/common";
extension-element-prefixes="exsl saxon">

<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
	
<xsl:key name="alphabetKey" match="newAlphabet" use="@col"/>
<xsl:variable name="alphabet">
	<xsl:apply-templates select="/test/alphabetList/alphabet"  mode="loadList"/>
</xsl:variable>
<xsl:variable name="alphabet-exslNodeSet" select="exsl:node-set($alphabet)"/>

<xsl:template match="numbers">
   <xsl:for-each select="number">
     <xsl:variable name="curPosition" select="position()"/>
     <xsl:for-each select="$alphabet-exslNodeSet">
       <!-- NB context changed to converted node set -->
       <xsl:copy-of select="key('alphabetKey', $curPosition)"/>
     </xsl:for-each>
   </xsl:for-each>
</xsl:template>

<xsl:template match="/">
   <xsl:apply-templates select="test/numbers"/>
</xsl:template>

<xsl:template match="alphabet" mode="loadList">
	<newAlphabet col="{@col}"><xsl:value-of select="."/></newAlphabet>
</xsl:template>

</xsl:stylesheet>


>..<snip/>...
> The key declaration must be then:
> <xsl:key name="alphabets" match="alphabet" use="@col"/>
>
> And later the usage of key():
> <xsl:template match="numbers">
>	<xsl:for-each select="number">
>		<xsl:variable name="curPosition" select="position()"/>
>		<xsl:for-each select="$alphabet-exslNodeSet">
>			<!-- context changed to converted node set -->
>			<xsl:copy-of select="key('myKey', $curPosition)"/>
>		</xsl:for-each>
>	</xsl:for-each>
></xsl:template>
>...<snip/>... 



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