Subject: RE: [xsl] How to give out XML-Tags? From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Thu, 5 Dec 2002 10:22:57 -0000 |
Use the doctype-system and doctype-public attributes of xsl:output, don't try to generate the DOCTYPE declaration by hand. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Sorin Marti > Sent: 05 December 2002 08:28 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] How to give out XML-Tags? > > > Hi all, > > I'd like to make a Transformation with XSL and want to get a > docBook-Source out of it. > For that reason I need to give out something like > > <!DOCTYPE Book PUBLIC "-//OASIS//DTD DocBook V4.1//EN" > "/usr/share/sgml/docbook_4/docbook.dtd"> > <book id="How-to" lang="de"> > > I tried to put that in <xsl:text>, but that doesen't work. > Choosing "xml" as output-method is also no solution. > > How do I do that, any advice? > > Thanks for your help > > Sorin > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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