Subject: [xsl] combining two variables to generate XPATH From: "bix xslt" <bix_xslt@xxxxxxxxxxx> Date: Tue, 17 Dec 2002 19:11:30 +0000 |
<?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE list SYSTEM "sort.dtd"> <?xml-stylesheet type="text/xsl" href="sort_1.xsl"?>
<list mode="normal"> <proc id="a" /> <proc id="h" /> <proc type="r" id="b"> <exec type="a"> <item idr="c" /> <item idr="d" /> </exec> </proc>
<proc type="e" id="c"> <dpnd> <item idr="a" /> <item idr="h" /> </dpnd> <exec type="a"> <item idr="e" /> <item idr="f" /> </exec> </proc> <proc id="d"> <dpnd> <item idr="g" /> </dpnd> </proc> <proc id="e" /> <proc id="f" />
<proc id="g" /> </list>
<xsl:template match="proc" name="depn"> <xsl:param name="node" select="." />
<xsl:value-of select="$node/@id" /> <xsl:if test="$node/dpnd"> <xsl:text> (</xsl:text> <xsl:call-template name="dispItem"> <xsl:with-param name="node" select="$node"/> <xsl:with-param name="type" select="dpnd"/> </xsl:call-template> <xsl:text>)</xsl:text> </xsl:if> <xsl:if test="$node/exec"> <xsl:text> "</xsl:text> <xsl:call-template name="dispItem"> <xsl:with-param name="node" select="$node"/> <xsl:with-param name="type" select="exec"/> </xsl:call-template> <xsl:text>"</xsl:text> </xsl:if> <br /> </xsl:template>
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