Re: [xsl] xsl filter problem

Subject: Re: [xsl] xsl filter problem
From: Dimitre Novatchev <dnovatchev@xxxxxxxxx>
Date: Thu, 26 Dec 2002 03:44:29 -0800 (PST)
Hi Yuval,

> When choosing "all cities" - the result is an empty table instead of 
> the list of all cities with the customers names.
> I tried to giva the param "city" a diect value of "*" or " '*' " and 
> it still didn't work.
> How can I pass a value to this param which will act like : <xsl:for-
> each select="customers/customer[city=*]"> ??


Use:

customers/customer[city=$city or $city = '*']


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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Current Thread
  • [xsl] xsl filter problem
    • Yuval - Thu, 26 Dec 2002 01:49:58 +0200
      • Mike Brown - Wed, 25 Dec 2002 17:59:34 -0700 (MST)
        • Yuval - Thu, 26 Dec 2002 12:10:01 +0200
          • Mike Brown - Thu, 26 Dec 2002 04:05:37 -0700 (MST)
      • <Possible follow-ups>
      • Dimitre Novatchev - Thu, 26 Dec 2002 03:44:29 -0800 (PST) <=