Re: [xsl] copy part of the original document

Subject: Re: [xsl] copy part of the original document
From: "Stefan Thull" <stefan@xxxxxxxxxx>
Date: Tue, 31 Dec 2002 16:08:11 +0100
Hello Joerg,


> -----Ursprüngliche Nachricht-----

> Betreff: Re: [xsl] copy part of the original document
>

> If you want to omit the whole section having a heading with a
> name attribute value of "Entwurf", simply write an *empty* template:
>  <xsl:template match="section[heading/@name='Entwurf']"/>
> Yes, that's all.
>
> J.Pietschmann
>
Thank you very much; that was it;  the empty tag omits the section and a
<xsl:template match="*|@*|text()">
   <xsl:copy>
     <xsl:apply-templates select="*|@*|text()" />
   </xsl:copy>
 </xsl:template>

copies the rest.

Now new-years party can start :-))

Stefan


>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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