RE: [xsl] Basic ques. about ancestor and child elements with same name

["Passin, Tom" <tpassin@xxxxxxxxxxxx>]

[Hubert Holtz]

> Lets say I have something like this:
> 
> <tree>
> 	<branch>
> 		<name> branch1 </name>
> 		<desc> long branch </desc> 
> 	
> 		<branch>
> 		  <name> branch2 </name>
> 		  <desc>  short branch</desc> 
> 		</branch>
> 
> 	</branch>
> </tree>
> 
> How can I output both branch names and their description, 
> without using any id or other attributes or other names for 
> the elements, my problem is how to output which have the same 
> name as the ancestor.

There are many ways, and this is probably the simplest -

<xsl:template match="/tree">
	<xsl:apply-templates select='branch'/>	
</xsl:template>

<xsl:template match='branch'>
<xsl:value-of select='name'/>
<xsl:value-of select='desc'/>
-- next branch --
<xsl:apply-templates select='branch'/>
</xsl:template>


This approach will walk the tree to any nesting depth.  You can tinker
with the display formating as you like.

Cheers,

Tom P

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