Subject: RE: [xsl] outputing tags From: "Passin, Tom" <tpassin@xxxxxxxxxxxx> Date: Mon, 6 Jan 2003 11:30:47 -0500 |
[ Sam Carleton] > Ok, then how do I do this: I have my xml file with all the > info I need in it. There is one element named <quote> which > contains quotes. Some quotes need to have line break ( > <br>'s in HTML). How do I denote a line break in the XML and > then how do I transform it? > It is all a matter of what you start with and what you want to end up with. The stylesheet transforms the one into the other. So what do you want to end up with? You say you want a "line break" in the XML, but XML inherently knows nothing about line breaks. Perhaps you mean that you want to create html output that happens to be well-formed xml as well? Then a <br/> element would just stay as is, if there is one in the source. Otherwise, no one can answer you without knowing how to determine where line breaks should occur. In general, if you just want to echo some existing element content (complete with <br/> or other elements), you would use xsl:copy-of. If you want to echo an element but change some of its child elements, use an identity transform where you specify templates only for the elements you want to change. The FAQs and archives contain examples. Cheers, Tom P XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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