Re: [xsl] possible to use copy-of without namespace

[Thomas Brand <brand@xxxxxxxxx>]

Hi Ken,

your solution with the template mode=".." is exactly what I was looking 
for, thanks indeed!!

At 03:33 08.01.2003 -0500, you wrote:
> At 2003-01-08 05:03 +0100, Thomas Brand wrote:
> > i try to get a 1:1 copy of a tree (using xsl:copy-of) without having the 
> > xmlns attribute set in the root node of the result tree.
> >
> > http://www.w3.org/TR/xslt#copy-of says "copying an element node copies 
> > the attribute nodes, namespace nodes and children of the element node as 
> > well as the element node itself"
> >
> > Is there a possibility to avoid the xmlns attribute added?
>
> Yes, by recreating each node found in the source instead of using xsl:copy-of.
>
> But why is it important to you that an unused xmlns attribute is hanging 
> around?

well, the guidelines for the output format are very strict. i guess one 
could also let them hang around maybe.. :)  there is a little chance that 
the delivered customer gets confused about it.

> Your test file is very confusing, though, because your <somechildnode> 
> construct isn't an element ... it is inside of PCDATA.  The element before 
> is in the ans namespace and the one following isn't ... since you are 
> using the ans namespace in the result, you will need it.

absolutely. the use of CDATA was a bloody workaround, which now has been 
corrected thanks to better knowledge!

i'll have to read about templates with mode attributes, never saw them.

<xsl:template mode="copy-no-ns" match="*">
  <xsl:element name="{name(.)}" namespace="{namespace-uri(.)}">
    <xsl:copy-of select="@*"/>
    <xsl:apply-templates mode="copy-no-ns"/>
  </xsl:element>
</xsl:template>


Greets from Berne,
 Thomas Brand


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