[xsl] How I could produce xml without xmlns:* ???

[Andrey Solonchuk <solo@xxxxxxxxxxxxxx>]

Hello xsl-list,

  How I could produce xml without xmlns:*

  I use the xsl
  
<?xml version='1.0'?>
<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0"
  xmlns:xalan="http://xml.apache.org/xalan";
  xmlns:my="http://my";
  xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias";
  exclude-result-prefixes="xalan my xsl xmlns axsl">
<xsl:namespace-alias stylesheet-prefix="axsl" result-prefix="xsl"/>

<xsl:output method="xml" indent="yes" xalan:indent-amount="5"/>

<xsl:key name="test" match="field" use="."/>
<my:import>
 <field id="1">11</field>
 <field id="2">11</field>
 <field id="3">12</field>
</my:import>

<xsl:template match="/">
 
 <xsl:copy-of select="document('')//my:import/"/>

</xsl:template>

</xsl:stylesheet>

and in output I get the next

<?xml version="1.0" encoding="UTF-8"?>
<my:import xmlns:my="http://my";                              !!!!!!
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";             !!!!!!
xmlns:xalan="http://xml.apache.org/xalan";                    !!!!!!
xmlns:axsl="http://www.w3.org/1999/XSL/TransformAlias";>      !!!!!!
 <field id="1">11</field>
 <field id="2">11</field>
 <field id="3">12</field>
</my:import>



-- 
Best regards,
 Andrey                          mailto:solo@xxxxxxxxxxxxxx



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