Subject: Re: [xsl] Sorting based on a calculated set of values From: AWK <ncam_tech@xxxxxxxx> Date: Mon, 13 Jan 2003 13:31:08 -0500 |
Thanks for the answer Jeni. On a related note, does anyone have information on how this actually happens in an XML parser? What I mean to ask is whether the parser goes through the xml file once, doing the calculation and sort at the same time, or does the xml tree get traversed multiple times in a process such as this? Thanks, AWK On 1/13/03 1:05 PM, "Jeni Tennison" <jeni@xxxxxxxxxxxxxxxx> wrote: > Hi Andrew, > >> And my out put is an HTML table table with four columns: >> Col 1: the item id >> Col 2: the a value >> Col 3: the b value >> Col 4: the product of a and b >> >> Can I sort my output by the fourth column? I know how to sort by the >> item id, a, or b, but don't know what I need to do to properly >> address the calculated value "column". > > You can sort by any expression you like by putting it in the select > attribute of xsl:sort. In this case you need: > > <xsl:for-each select="item"> > <xsl:sort select="a * b" data-type="number" /> > <tr> > <td><xsl:value-of select="@id" /></td> > <td><xsl:value-of select="a" /></td> > <td><xsl:value-of select="b" /></td> > <td><xsl:value-of select="a * b" /></td> > </tr> > </xsl:for-each> > > Cheers, > > Jeni > > --- > Jeni Tennison > http://www.jenitennison.com/ > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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