Subject: Re: [xsl] how to "save" a context? From: S Woodside <sbwoodside@xxxxxxxxx> Date: Tue, 14 Jan 2003 16:38:40 -0500 |
"S Woodside" <sbwoodside@xxxxxxxxx> wrote in message news:1D578741-27F8-11D7-AD3E-000393414368@xxxxxxxxxxxxGah! It's huge!assigned
Seriously it looks like this will generate a string that, whento a variable, and selected upon, will act as the correct XPath. Is that right?
Yes, actually this snippet processes a nodeset of nodes and generates a set of strings (XPath expressions) for each of them. You can simplify it a bit to work only on a single node (get rid of the outermost xsl:for-each).
It has: <xsl:value-of select="msxsl:node-set($theResult)"/>
Does it require MSxml? Can I turn $theResult (which is a string, right?) into an XPath expression I can use in a select statement, without needing MSXML?
Actually, the xxx:node-set extension function is not required.
Just get rid of it and the msxsl namespace, too.
===== Cheers,
Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL
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