[xsl] Generating variable DOCTYPE

[Cams Ismael <Ismael.Cams@xxxxxxxxxxxxxxx>]

Hello,

I am trying to transform an xml file into another xml file by means of a
stylesheet. This stylesheet takes as input parameter the location of the DTD
belonging to the generated xml file. What I would like to do is:

	<xsl:param name="DTDLocation"/>
	<xsl:output method="xml" encoding="UTF-8"
doctype-system="{$DTDLocation}"/>

This is possible in XSLT 1.1, but not in XSLT 1.0. Another way is to write
an extension function that writes the DOCTYPE to the output. However I
prefer a solution in XSLT 1.0 (if I am correct XSLT 1.1 became never a
Recommendation) and without extension functions. Is this possible somehow ?

Thanks in advance.

Kind regards,
Ismaël





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