Re: [xsl] Finding the path from the filename

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

This is a FAQ and has been answered several times on this list:

FXSL is ideally suited for such tasks. See for example:

http://sources.redhat.com/ml/xsl-list/2002-03/msg00399.html



=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL



"Thomas V. Nielsen" <thomas@xxxxxxxxxxxxx> wrote in message
news:0B777195ADF44B438161E97E6FB2A29D062EBE@xxxxxxxxxxxxxxxxx
> In a XSLT I receive a parameter with a full path and file name, like;
> 
> C:\Data\Test\File.xml
> 
> I have tried fumbling with substring and substring-before, but with
no
> luck.
> 
> What I need is the full path without the file name, like
C:\Data\Test\
> 
> Sometimes parameter looks like this
> 
> ..\Test\File.xml
> 
> And also here I need to find the path, like ..\Test\
> 
> Any suggestions in how to use the substring with some iteration?
> 
> /Thomas
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

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