Subject: Re: [xsl] Selecting node at a certain position from a nodeset From: Marco Guazzone <sguazt@xxxxxxxxxxx> Date: Wed, 22 Jan 2003 14:48:09 +0100 (CET) |
Hi David, so how do you solve this problem? Is the exsl:node-set solution the better one (respect to computation time and memory consumption) ? Regards, -------------------------------- Marco Guazzone Software Engineer Kerbero S.r.L. - Gruppo TC Viale Forlanini, 36 Garbagnate M.se (MI) 20024 - Italy mail: marco.guazzone@xxxxxxxxxxx www: http://www.kerbero.com Tel. +39 02 99514.247 Fax. +39 02 99514.399 -------------------------------- On Wed, 22 Jan 2003, David Carlisle wrote: > > > select="$sections/section[@group=1]/item[@id=1][$pos]"/> > > the $pos item node that is a child of section[@group=1] > and has @id=1. > > Since you have uniue ids within each section, if $pos is 1 > you should get the same as > > > select="$sections/section[@group=1]/item[@id=1]"/> > > but id pos is any number other than 1 you should get nothing as > there is only one item in each step satisfying [@id=1] so position() is > always equal to 1. > > David > > > ________________________________________________________________________ > This e-mail has been scanned for all viruses by Star Internet. The > service is powered by MessageLabs. For more information on a proactive > anti-virus service working around the clock, around the globe, visit: > http://www.star.net.uk > ________________________________________________________________________ > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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