Subject: [xsl] dynamic construction of path based on param From: raven <ra5en2000@xxxxxxxxx> Date: Wed, 22 Jan 2003 10:00:54 -0800 (PST) |
I want to dynamically construct a path based on a param called $course. Here is my current code: <xsl:if test='contains($course, "510")'> <xsl:variable name="path" select="x510" /> </xsl:if> <xsl:if test='contains($course, "340")'> <xsl:variable name="path" select="x340" /> </xsl:if> <xsl:apply-templates select='syllabus/$path'/> When I run the transformation the transformer responds with "pattern empty," which tells me that it is not changing the $path variable properly or that I have not encoded it correctly. It is, however, receiving the parameter correctly as I tested for that. How do I construct this correctly? Also, ideally I'd just like to use $course in the path. Thank you. ra5en@xxxxxxxxx __________________________________________________ Do you Yahoo!? Yahoo! Mail Plus - Powerful. Affordable. Sign up now. http://mailplus.yahoo.com XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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