Re: [xsl] Axis-Name help

[Francis Norton <francis@xxxxxxxxxxx>]

Hi Bix,

bix xslt wrote:

> I want to create a nodeset for a variable which contains each column 
> of data.
>
> My limited knowledge made me think this might work...but as testing 
> will show, it does not:

No, it doesn't. You're not too far off - here's something that 
illustrates what I think you want do (you could make it shorter by 
eliminating the columnCells variables, but don't do that until you're 
comfortable with what's going on):

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

 <xsl:template match="/">
   <matrix>
     <xsl:for-each select="grandp/parent">
       <xsl:variable name="pos" select="position()"/>
       <xsl:variable name="columnCells" 
select="//parent/child[position() = $pos]"/>
       <xsl:call-template name="column">
         <xsl:with-param name="columnCells" select="$columnCells"/>
       </xsl:call-template>
     </xsl:for-each>
   </matrix>
 </xsl:template>

 <xsl:template name="column">
   <xsl:param name="columnCells"/>
   <column>
     <xsl:for-each select="$columnCells">
       <xsl:copy-of select="."/>
     </xsl:for-each>
   </column>
 </xsl:template>
</xsl:stylesheet>

As you realised, you have to "freeze" the current position, but you can 
then use it very simply.

Francis.


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