Subject: Re: [xsl] constructing the Node Sets From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 29 Jan 2003 15:50:14 GMT |
> I expected that the intersection of a and b will produce a count of 2, ah. In that case you asked the wrong question. Your node sets are disjoint, no node has both @name='Asm' and @name='Cmp' so the intersection of the sets $a and $b is empty. You don't want the intesection of the sets, you want all elements of $a that have a string value equal to some member of $b, that's easier than the question you asked, $a[.=$b] except that if you have the possibility of duplicate obid values you may need to remove duplicates as well. Note that $a[ count( . | $b ) = count( $b ) ] is the same as $b[ count( . | $a ) = count( $a ) ] it really is the nodes in both $a and $b, but $a[.=$b] is not the same as $b[.=$a] one is the set of nodes in $a the other is the set in $b. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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