Re: [xsl] constructing the Node Sets

Subject: Re: [xsl] constructing the Node Sets
From: David Carlisle <davidc@xxxxxxxxx>
Date: Wed, 29 Jan 2003 15:50:14 GMT
> I expected that the intersection of a and b will produce a count of 2,

ah. In that case you asked the wrong question.

Your node sets are disjoint, no node has both  @name='Asm' and @name='Cmp'
so the intersection of the sets $a and $b is empty.

You don't want the intesection of the sets, you want all elements of $a
that have a string value equal to some member of $b, that's easier than
the question you asked,

$a[.=$b]

except that if you have the possibility of duplicate obid values you may
need to remove duplicates as well.

Note that
$a[ count( . | $b ) = count( $b ) ]
is the same as 
$b[ count( . | $a ) = count( $a ) ]
it really is the nodes in both $a and $b,

but

$a[.=$b]

is not the same 
as


$b[.=$a]

one is the set of nodes in $a the other is the set in $b.


David


________________________________________________________________________
This e-mail has been scanned for all viruses by Star Internet. The
service is powered by MessageLabs. For more information on a proactive
anti-virus service working around the clock, around the globe, visit:
http://www.star.net.uk
________________________________________________________________________

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread