Subject: Re: [xsl] Retrieving Position-Nr of Element From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 30 Jan 2003 09:35:59 GMT |
> is there a way of efficiently get the position() of A in that node-set sets do not have any order (that's the difference between a set and a list). the value of position() depends on the current node list used to select the node, not the node set that contains the node. If you select a node with . or .. or parent:: then it will always have position()=1 for example. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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