Re: [xsl] Newby Question reformatting xml

[Oleg Tkachenko <olegt@xxxxxxxxxxxxx>]

Michael A. Thompson wrote:

> My XSL file:
>
> <?xml version="1.0" encoding="UTF-8" ?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
> version="1.0">
>
>     <xsl:output method="xml" indent="yes"/>
>     
>     <xsl:template match="AAA">
>         <xsl:element name="AAA">
>             <xsl:apply-templates select="DDD" />
>         </xsl:element>
>     </xsl:template>
>     
>     <xsl:template match="DDD">
>         <xsl:element name="DDD">
>             <xsl:apply-templates select="BBB"></xsl:apply-templates>
>         </xsl:element>
>        
>     </xsl:template>
>     
>     <xsl:template match="BBB">
>         <xsl:element name="BBB">
>             <xsl:attribute name="num">
>                 <xsl:value-of select="//DDD/@id"></xsl:value-of>
>             </xsl:attribute>
>             <xsl:value-of select="."></xsl:value-of>
>         </xsl:element>
>     </xsl:template>
>     
> </xsl:stylesheet>

Try simple one:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
    <xsl:template match="AAA">
        <AAA>
            <xsl:apply-templates select="DDD"/>
        </AAA>
    </xsl:template>
    <xsl:template match="DDD">
        <DDD>
            <xsl:apply-templates select="BBB"/>
        </DDD>
    </xsl:template>
    <xsl:template match="BBB">
        <BBB num="{ancestor::DDD[1]/@id}">
            <xsl:value-of select="."/>
        </BBB>
    </xsl:template>
</xsl:stylesheet>

--
Oleg Tkachenko
Multiconn Technologies, Israel


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