Subject: Re: [xsl] Getting position of parent From: Jeni Tennison <jeni@xxxxxxxxxxxxxxxx> Date: Thu, 20 Feb 2003 15:36:39 +0000 |
Hi Geoff, > So what I want to do is make $pageNumber = position() -1 for the > page node while I am in the (grandchild) Field node. How can I > accomplish this? I'm scratching my head on this one Try counting the number of preceding sibling Page elements the ancestor Page element has and adding one to get the position: count(ancestor::Page/preceding-sibling::Page) + 1 By the way, you might find your template a bit clearer if you used an attribute value template to create the style attribute: <xsl:template match="Field"> <xsl:variable name="pageNumber" select="count(ancestor::Page/preceding-sibling::Page) + 1" /> <xsl:variable name="top" select="@Top * 0.06666 + ($pageNumber * $pageHeight)" /> <div style="position: absolute; top: {$top}; left: {@Left * 0.06666}; font-size: {@FontSize}pt; font-family: {@FontFamily};"> <xsl:value-of select="." /> </div> </xsl:template> Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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