[xsl] Re: Can one _generate_ namespace nodes?

["Dimitre Novatchev" <dnovatchev@xxxxxxxxx>]

> In XSLT 1.0 the usual circumvention is to create an RTF containing the
> required namespace node, and then copy it (which requires xx:node-set):
>
> <xsl:variable name="dummy">
>  <xsl:element name="{$prefix}:xxx" namespace="{$uri}"/>
> </xsl:variable>
>
> ...
>
> <xsl:copy-of
>   select="xx:node-set($dummy)/*/namespace::*[name()=$prefix]"/>
>
> Copying of namespace nodes is defined by an erratum to XSLT 1.0.

In case the prefix and the namespace-uri are known in advance, the namespace
declaration can be put within the xsl:stylesheet element.

This will avoid the need to create an RTF -- just use:

<xsl:copy-of select="document('')/*/namespace::*[name()=$prefix]"/>


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL





 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list