Subject: [xsl] Re: Can one _generate_ namespace nodes? From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Sat, 22 Feb 2003 12:32:35 +0100 |
> In XSLT 1.0 the usual circumvention is to create an RTF containing the > required namespace node, and then copy it (which requires xx:node-set): > > <xsl:variable name="dummy"> > <xsl:element name="{$prefix}:xxx" namespace="{$uri}"/> > </xsl:variable> > > ... > > <xsl:copy-of > select="xx:node-set($dummy)/*/namespace::*[name()=$prefix]"/> > > Copying of namespace nodes is defined by an erratum to XSLT 1.0. In case the prefix and the namespace-uri are known in advance, the namespace declaration can be put within the xsl:stylesheet element. This will avoid the need to create an RTF -- just use: <xsl:copy-of select="document('')/*/namespace::*[name()=$prefix]"/> ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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