Subject: Re: [xsl] different first element in a list From: Lorenzo De Tomasi <detomasi.liste@xxxxxxxxx> Date: Mon, 24 Feb 2003 00:55:19 +0100 |
on 23-02-2003 23:08, Michael Kay at michael.h.kay@xxxxxxxxxxxx wrote: > It is displaying the first row twice because you have asked it to. > > Your logic is > > for-each language that is the first of its @type > display the language > for each language of this @type > display the language > > Just remove the code corresponding to the outer "display the language". But how can I display each language of this type except the first? If I remove the code corresponding to the outer "display the language" I don't understand what's the code that indicates where to put the language of this @type except the first :( The logic I want is: for-each language that is the first of its @type label: display the language for each language of this @type except the first display the language What I want to obtain is 1. If in the Xml I have a single 'mother tongue' and a single 'other tongue': ______________________________________________ mother tongue Italian other tongue English speak: good read: excellent write: good ______________________________________________ 2. If in the Xml I have more 'mother tongue's and 'other tongue's: ______________________________________________ mother tongues German Italian other tongues English speak: good read: excellent write: good Français speak: basic read: basic write: basic ______________________________________________ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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