Subject: [xsl] Re: Re: Re: Can one _generate_ namespace nodes? From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Tue, 25 Feb 2003 21:07:01 +0100 |
"Joseph Kesselman" <keshlam@xxxxxxxxxx> wrote in message news:OFAE3EAC25.E1215AC5-ON85256CD8.004D468A-85256CD8.004E5301@xxxxxxxxxxxxx > Quoth "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> > >What about the following: > > >... > > <xsl:template match="/"> > > <newxsl:stylesheet version="1.0" > > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > > <newxsl:text>foo</newxsl:text> > > </newxsl:stylesheet> > > </xsl:template> > > Hmmmmmm. That uses a literal result element with explicit namespace > declaration attribute to work around the limitation on <xsl:attribute>. > Looks like it might actually do the trick... though it's just subtle > enough that I'm not sure I want to take the time to teach it. <smile/> Yes, this is the simplest possible way to do the job. All other ways involve some kind of a trick -- e.g. copying artificial attributes. ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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