Subject: [xsl] line feeds when outputing as text From: Sam Carleton <sam@xxxxxxxxxxxxxx> Date: Mon, 3 Mar 2003 15:13:31 -0500 |
Folks, I have an xml file that contains item elements. Some items have an url attribute. I am trying to write a xslt program to give me each url on a separate line. I figured this would work: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text" indent="yes"/> <xsl:template match="/"> <xsl:apply-templates select=".//item[string-length(@url)!=0]"/> </xsl:template> <xsl:template match="item"> <xsl:value-of select="@url"/> </xsl:template> </xsl:stylesheet> The problem with this is that there is no line breaking between the different URL's. I tried adding both a and (forgetting which one UNIX likes): <xsl:template match="item"> <xsl:value-of select="@url"/> </xsl:template> And that still had no effect. Finally I tried to tack something on the front and that DID work: <xsl:template match="item"> :<xsl:value-of select="@url"/> </xsl:template> I could live with this except for the fact that there is no line on the last entry so my shell script is not picking up the last entry. How do I get a linefeed at the end? Sam XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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