Subject: Re: [xsl] Determining the extension of the output file? From: "bix xslt" <bix_xslt@xxxxxxxxxxx> Date: Wed, 05 Mar 2003 22:44:26 +0000 |
Hope that helps, bix
From: Esther Parrilla Endrino <esther.parrilla@xxxxxxxxxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Determining the extension of the output file? Date: Wed, 05 Mar 2003 15:38:40 +0100
Hello all,
I am doing a very simple example that transforms an XML file into and HTML file after applying and XSL using libxml2 and libxslt.
I use the xmlSaveFile() function to save to disk the output HTML file.
For that I put in my code:
...
res = xsltApplyStylesheet(cur, doc, params)
xmlSaveFile("output.html", res);
...
But my problem is that sometimes I am going to use an XSL that shall transform the XML to HTML and sometimes I shall use other XSL that shall transform the XML to another different XML... and I would like to call my output file output.html or output.xml depending on the type of XSL I apply.
So I have thought that when I am parsing my XSL with the function xsltParseStylesheetFile() I should try to determine if there is an <html...> tag in the XSL or and <xml...>. I have been looking for a function in the libxslt API that can di this for mi but I haven´t found any :( ...
Does anybody knows if there is a function in the libxslt API that can do that?
Should I look in the libxml2 API instead?
Thanks in advance!
esther
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Esther Parrilla Endrino Ground Segment Systems Division DEIMOS SPACE S.L. e-mail: esther.parrilla@xxxxxxxxxxxxxxxx tel: 00 34 91 806 34 57
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